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Varsity KA Admission Model Test 72
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Physics
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What is the de Broglie wavelength of an electron with energy? 500 eV
A
17.68 Å
B
24.86 Å
C
3.55 Å
D
2.55 Å E = hc λ ∴ λ = hc E = 6.63×10−34×3×108 500×1.6×10−19 = 2.48 × 10−9m = 24.86Å
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