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Varsity KA Admission Model Test 46
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Question 1 of 100
Chemistry
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Polar coordinate of the point is- (√3, 1)
A
(2, π/4)
B
(2, π/6)
C
(1, π/4)
D
(0, π/4) r = √x2 + y2 (x, y) = (√3, 1) ⇒ r = √(√3)2 + 12 = √3 + 1 = 2. θ = tan−1 1 √3 = π 6 ∴ (√3, 1) = (2, π 6 )
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